Subjects algebra

Rectangle Dimensions 854C8B

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1. **Problem statement:** A rectangular land has a length equal to twice its width, and its area is 162 cm². Find the length and width. 2. **Formula:** Area of rectangle = length \times width. 3. **Let width = $w$ cm. Then length = $2w$ cm.** 4. **Area equation:** $$2w \times w = 162$$ 5. Simplify: $$2w^2 = 162$$ 6. Divide both sides by 2: $$\cancel{2}w^2 = \frac{162}{\cancel{2}} \Rightarrow w^2 = 81$$ 7. Take square root: $$w = \sqrt{81} = 9$$ cm 8. Find length: $$l = 2w = 2 \times 9 = 18$$ cm **Answer:** Width = 9 cm, Length = 18 cm.