1. **State the problem:** We are given an expression for the perimeter of a rectangle as $8w$, where $w$ is the width in inches. 2. **Recall the formula for the perimeter of a rectangle:** $$P = 2(\text{width} + \text{height})$$ 3. **Set up the equation using the given expression:** $$8w = 2(w + h)$$ 4. **Solve for the height $h$:** $$8w = 2w + 2h$$ $$8w - 2w = 2h$$ $$6w = 2h$$ $$\cancel{2} \cdot 3w = \cancel{2} \cdot h$$ $$3w = h$$ 5. **Interpret the result:** The height $h$ is 3 times the width $w$. 6. **Check the options:** - The height of the rectangle is 4 times its width. (False) - The height of the rectangle is 3 times its width. (True) - The perimeter of the rectangle is 4 times its width. (False, perimeter is $8w$) - The perimeter of the rectangle is 3 times its height. (False, perimeter is $8w$, height is $3w$) **Final answer:** The height of the rectangle is 3 times its width.