Subjects algebra

Rectangle Width 6D1Cea

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1. **State the problem:** We have a rectangle with length 8 feet and area less than 168 square feet. We want to find an inequality representing the width $x$ and solve it. 2. **Recall the formula for the area of a rectangle:** $$\text{Area} = \text{length} \times \text{width}$$ 3. **Set up the inequality:** Since the area is less than 168, we write: $$8 \times x < 168$$ 4. **Solve the inequality for $x$:** Divide both sides by 8: $$\frac{\cancel{8} \times x}{\cancel{8}} < \frac{168}{8}$$ $$x < 21$$ 5. **Interpretation:** The width $x$ must be less than 21 feet. 6. **Select the correct inequality from the options:** The correct inequality is: $$8x < 168$$ **Final answer:** $$x < 21$$