1. **State the problem:** We need to find the dimensions (width and length) of a rectangular base where the length is 70 ft less than twice the width, and the perimeter is 790 ft. 2. **Write down the formulas and variables:** Let the width be $w$ ft. The length $l$ is given by: $$l = 2w - 70$$ The perimeter $P$ of a rectangle is: $$P = 2(l + w)$$ 3. **Set up the equation using the perimeter:** $$790 = 2((2w - 70) + w)$$ 4. **Simplify inside the parentheses:** $$790 = 2(3w - 70)$$ 5. **Distribute the 2:** $$790 = 6w - 140$$ 6. **Add 140 to both sides:** $$790 + 140 = 6w$$ $$930 = 6w$$ 7. **Divide both sides by 6:** $$\cancel{6}w = \frac{930}{\cancel{6}}$$ $$w = 155$$ 8. **Find the length using $w=155$:** $$l = 2(155) - 70 = 310 - 70 = 240$$ **Final answer:** The width of the base is $155$ ft. The length of the base is $240$ ft.