Subjects algebra

Rental Cost Equality 142A3D

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1. **State the problem:** John wants to find the distance at which the cost of renting a car from Long Hauler Rentals and Discount Rentals is the same. 2. **Define variables and write cost functions:** Let $d$ be the distance in kilometers. - Long Hauler Rentals cost: $$C_1 = 50 + 0.12d$$ - Discount Rentals cost: $$C_2 = 40 + 0.20d$$ 3. **Set the costs equal to find the distance:** $$50 + 0.12d = 40 + 0.20d$$ 4. **Solve for $d$:** Subtract 40 from both sides: $$50 - 40 + 0.12d = 0.20d$$ Simplify: $$10 + 0.12d = 0.20d$$ Subtract $0.12d$ from both sides: $$10 + \cancel{0.12d} = 0.20d - \cancel{0.12d}$$ $$10 = 0.08d$$ 5. **Divide both sides by 0.08:** $$\frac{10}{\cancel{0.08}} = \frac{0.08d}{\cancel{0.08}}$$ $$125 = d$$ 6. **Interpretation:** The cost will be the same when John drives 125 kilometers. **Final answer:** $$\boxed{125\text{ km}}$$