1. **State the problem:** John wants to find the distance at which the cost of renting a car from Long Hauler Rentals and Discount Rentals is the same.
2. **Define variables and write cost functions:** Let $d$ be the distance in kilometers.
- Long Hauler Rentals cost: $$C_1 = 50 + 0.12d$$
- Discount Rentals cost: $$C_2 = 40 + 0.20d$$
3. **Set the costs equal to find the distance:**
$$50 + 0.12d = 40 + 0.20d$$
4. **Solve for $d$:**
Subtract 40 from both sides:
$$50 - 40 + 0.12d = 0.20d$$
Simplify:
$$10 + 0.12d = 0.20d$$
Subtract $0.12d$ from both sides:
$$10 + \cancel{0.12d} = 0.20d - \cancel{0.12d}$$
$$10 = 0.08d$$
5. **Divide both sides by 0.08:**
$$\frac{10}{\cancel{0.08}} = \frac{0.08d}{\cancel{0.08}}$$
$$125 = d$$
6. **Interpretation:** The cost will be the same when John drives 125 kilometers.
**Final answer:** $$\boxed{125\text{ km}}$$
Rental Cost Equality 142A3D
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.