1. **State the problem:** We want to find the distance $x$ (in kilometers) where the rental costs from company A and company B are equal.
2. **Define variables and write the cost functions:**
- Company A charges 29 per week plus 13 per kilometer, so cost is $C_A = 29 + 13x$.
- Company B charges 85 per week plus 6 per kilometer, so cost is $C_B = 85 + 6x$.
3. **Set up the equation for equal costs:**
$$29 + 13x = 85 + 6x$$
4. **Solve for $x$:**
Subtract 6x from both sides:
$$29 + \cancel{13x} - \cancel{6x} = 85 + \cancel{6x} - \cancel{6x} \implies 29 + 7x = 85$$
Subtract 29 from both sides:
$$29 - 29 + 7x = 85 - 29 \implies 7x = 56$$
Divide both sides by 7:
$$\frac{\cancel{7}x}{\cancel{7}} = \frac{56}{7} \implies x = 8$$
5. **Interpretation:** You must drive 8 kilometers for the rental costs of both companies to be the same.
**Final answer:** $x = 8$ kilometers.
Rental Cost Equality 8377E0
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