1. **Problem Statement:** We have a line segment from point $(-8,1)$ to point $(8,-8)$ on the coordinate plane. We need to draw the "rise" and "run" segments and find the slope of the line in simplest form. 2. **Formula for slope:** The slope $m$ of a line passing through points $(x_1,y_1)$ and $(x_2,y_2)$ is given by: $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ This represents the "rise" (change in $y$) over the "run" (change in $x$). 3. **Calculate rise and run:** - Rise $= y_2 - y_1 = -8 - 1 = -9$ - Run $= x_2 - x_1 = 8 - (-8) = 16$ 4. **Slope calculation:** $$m = \frac{-9}{16}$$ This fraction is already in simplest form since 9 and 16 have no common factors other than 1. 5. **Interpretation:** - The "rise" is a vertical line segment of length 9 units downward (since it is negative). - The "run" is a horizontal line segment of length 16 units to the right. 6. **Summary:** - Rise segment: vertical line from $(8,1)$ down to $(8,-8)$ - Run segment: horizontal line from $(-8,1)$ to $(8,1)$ - Slope of the line: $-\frac{9}{16}$ This slope means the line falls 9 units for every 16 units it moves to the right.