1. **Problem statement:** We want to find the correct equation for the rocket's weight $W$ at time $t$ where $0 \leq t \leq T$, given initial weight $W_1$ and final weight $W_T$ at time $T$.
2. **Understanding the problem:** The weight decreases linearly as fuel is burnt, so $W$ changes from $W_1$ at $t=0$ to $W_T$ at $t=T$.
3. **General linear equation:** A linear function from $(0, W_1)$ to $(T, W_T)$ can be written as:
$$W = W_1 + m t$$
where $m$ is the slope.
4. **Calculate slope $m$:**
$$m = \frac{W_T - W_1}{T - 0} = \frac{W_T - W_1}{T}$$
5. **Substitute slope into equation:**
$$W = W_1 + \frac{W_T - W_1}{T} t$$
6. **Rewrite to show weight decrease:** Since $W_T < W_1$, rewrite as:
$$W = W_1 - \frac{W_1 - W_T}{T} t$$
7. **Check given options:** The correct formula matches:
$$W = W_1 - \left(\frac{W_1 - W_T}{T}\right) t$$
**Final answer:**
$$W = W_1 - \left(\frac{W_1 - W_T}{T}\right) t$$
Rocket Weight B0Beba
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