Subjects algebra

Satellite Distance 7Ac25B

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1. **Stating the problem:** We need to find the distance a satellite travels in 8 seconds using a proportion from part (a). 2. **Understanding proportions:** A proportion states that two ratios are equal. If the satellite travels a certain distance in a given time, we can set up a ratio of distance to time and use it to find the unknown distance for 8 seconds. 3. **Formula:** If $d_1$ is the distance traveled in $t_1$ seconds, and $d_2$ is the distance traveled in $t_2$ seconds, then the proportion is: $$\frac{d_1}{t_1} = \frac{d_2}{t_2}$$ 4. **Using the proportion:** From part (a), suppose the satellite travels $d_1$ kilometers in $t_1$ seconds. We want to find $d_2$ when $t_2 = 8$ seconds. 5. **Solving for $d_2$:** Multiply both sides by $t_2$: $$d_2 = \frac{d_1}{t_1} \times t_2$$ 6. **No rounding:** Keep all computations exact as per instructions. 7. **Final answer:** The distance the satellite travels in 8 seconds is $$d_2 = \frac{d_1}{t_1} \times 8$$ kilometers, where $d_1$ and $t_1$ are from part (a).