Subjects algebra

Satellite Speed A5F54C

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1. **State the problem:** We need to find the speed (miles per hour) of Space Explorer A and Space Explorer B, then compare their speeds. 2. **Formula for speed:** Speed is calculated as $$\text{speed} = \frac{\text{distance}}{\text{time}}$$. 3. **Calculate speed of Space Explorer B:** Given distance = 125000 miles and time = 25 hours, $$\text{speed}_B = \frac{125000}{25} = 5000 \text{ miles per hour}$$. 4. **Calculate speed of Space Explorer A:** Using the table, pick any pair (x, y). For example, at 4 hours, distance = 36000 miles, $$\text{speed}_A = \frac{36000}{4} = 9000 \text{ miles per hour}$$. Check with other pairs to confirm speed is constant: At 6 hours, speed = $$\frac{54000}{6} = 9000$$ mph, consistent. 5. **Compare speeds:** $$\text{difference} = \text{speed}_A - \text{speed}_B = 9000 - 5000 = 4000$$ miles per hour. Since 9000 > 5000, Space Explorer A travels 4000 miles per hour faster than Space Explorer B. **Final answer:** Space Explorer A travels 4000 miles per hour faster than Space Explorer B.