1. **Stating the problem:**
Sam's savings and Ali's savings relate as follows: $\frac{3}{5}$ of Sam's savings equals $\frac{1}{4}$ of Ali's savings.
Ali saves 56 more than Sam.
We need to find:
(a) The ratio of Sam's savings to Ali's savings.
(b) Their total amount of savings.
2. **Define variables:**
Let Sam's savings be $S$ and Ali's savings be $A$.
3. **Write the equation from the problem:**
$$\frac{3}{5}S = \frac{1}{4}A$$
4. **Express $A$ in terms of $S$:**
Multiply both sides by 20 (the least common multiple of 5 and 4) to clear denominators:
$$20 \times \frac{3}{5}S = 20 \times \frac{1}{4}A$$
$$4 \times 3S = 5A$$
$$12S = 5A$$
Divide both sides by 5:
$$\cancel{12}S \times \frac{1}{\cancel{5}} = \cancel{5}A \times \frac{1}{\cancel{5}}$$
$$\frac{12}{5}S = A$$
So,
$$A = \frac{12}{5}S$$
5. **Use the information that Ali saves 56 more than Sam:**
$$A = S + 56$$
Substitute $A$ from step 4:
$$\frac{12}{5}S = S + 56$$
6. **Solve for $S$:**
Bring all terms to one side:
$$\frac{12}{5}S - S = 56$$
Rewrite $S$ as $\frac{5}{5}S$:
$$\frac{12}{5}S - \frac{5}{5}S = 56$$
Subtract fractions:
$$\frac{12 - 5}{5}S = 56$$
$$\frac{7}{5}S = 56$$
Multiply both sides by $\frac{5}{7}$:
$$S = 56 \times \frac{5}{7}$$
Simplify:
$$S = 8 \times 5 = 40$$
7. **Find $A$:**
$$A = S + 56 = 40 + 56 = 96$$
8. **Find the ratio of Sam's savings to Ali's savings:**
$$S : A = 40 : 96$$
Simplify by dividing both by 8:
$$\cancel{40} : \cancel{96} = 5 : 12$$
9. **Find their total savings:**
$$S + A = 40 + 96 = 136$$
**Final answers:**
(a) The ratio of Sam's savings to Ali's savings is $5 : 12$.
(b) Their total amount of savings is 136.
Savings Ratio 75Ae01
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