Subjects algebra

Scientific Notation Addition 995D6D

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1. **Stating the problem:** Solve the expression: $$14.8 \times 10^{-5} + 6.02 \times 10^{-4}$$ 2. **Formula and rules:** When adding numbers in scientific notation, the exponents must be the same. 3. **Rewrite both terms with the same exponent:** $$14.8 \times 10^{-5} = 1.48 \times 10^{-4}$$ 4. **Add the coefficients:** $$1.48 \times 10^{-4} + 6.02 \times 10^{-4} = (1.48 + 6.02) \times 10^{-4}$$ 5. **Calculate the sum:** $$7.5 \times 10^{-4}$$ 6. **Final answer:** $$14.8 \times 10^{-5} + 6.02 \times 10^{-4} = 7.5 \times 10^{-4}$$