1. **Stating the problem:**
We are given a sequence defined by the formula $H_n = 2400n + 67600$.
2. **Understanding the formula:**
This is a linear sequence where $n$ is the term number, $2400$ is the coefficient multiplying $n$, and $67600$ is the constant term.
3. **Interpreting the question:**
Since the user also mentions $J_n$ and $N$ without a formula, we focus on the given formula for $H_n$ as the first problem.
4. **Example calculation:**
To find the value of $H_n$ for a specific $n$, substitute $n$ into the formula.
For example, for $n=1$:
$$H_1 = 2400 \times 1 + 67600 = 2400 + 67600 = 70000$$
For $n=2$:
$$H_2 = 2400 \times 2 + 67600 = 4800 + 67600 = 72400$$
5. **Summary:**
The formula $H_n = 2400n + 67600$ gives the $n$th term of the sequence by multiplying $n$ by 2400 and adding 67600.
This completes the solution for the first problem.
Sequence Hn D691D6
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