Subjects algebra

Sequence Hn D691D6

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1. **Stating the problem:** We are given a sequence defined by the formula $H_n = 2400n + 67600$. 2. **Understanding the formula:** This is a linear sequence where $n$ is the term number, $2400$ is the coefficient multiplying $n$, and $67600$ is the constant term. 3. **Interpreting the question:** Since the user also mentions $J_n$ and $N$ without a formula, we focus on the given formula for $H_n$ as the first problem. 4. **Example calculation:** To find the value of $H_n$ for a specific $n$, substitute $n$ into the formula. For example, for $n=1$: $$H_1 = 2400 \times 1 + 67600 = 2400 + 67600 = 70000$$ For $n=2$: $$H_2 = 2400 \times 2 + 67600 = 4800 + 67600 = 72400$$ 5. **Summary:** The formula $H_n = 2400n + 67600$ gives the $n$th term of the sequence by multiplying $n$ by 2400 and adding 67600. This completes the solution for the first problem.