1. The problem appears to be identifying the missing numbers in the boxes in the sequence: \(\boxed{?} \rightarrow \boxed{?} \rightarrow \boxed{?} \rightarrow 46 \rightarrow 20 \rightarrow 7\). 2. To solve this, we need to find a pattern or rule that connects these numbers. 3. Let's analyze the known numbers: 46, 20, and 7. 4. Calculate the differences: \(46 - 20 = 26\), \(20 - 7 = 13\). 5. The differences are 26 and 13, which suggests the differences might be halving each time. 6. If the difference halves each step, the previous difference before 26 would be \(26 \times 2 = 52\), and before that \(52 \times 2 = 104\). 7. Starting from 46 and adding 26 gives 72, but since the sequence goes backward, we subtract differences to find previous numbers. 8. So, the number before 46 is \(46 + 26 = 72\), before that \(72 + 52 = 124\), and before that \(124 + 104 = 228\). 9. Therefore, the sequence is: \(228 \rightarrow 124 \rightarrow 72 \rightarrow 46 \rightarrow 20 \rightarrow 7\). 10. The numbers in the boxes are 228, 124, and 72. Final answer: \(\boxed{228}, \boxed{124}, \boxed{72}\).