1. The problem asks to fill in the missing terms for sequences B and C based on the given terms and nth term formulas. 2. For Sequence A, the nth term is given as $21 - n$. The terms are 20, 19, 18, 17 which matches $21 - 1 = 20$, $21 - 2 = 19$, etc. 3. For Sequence B, the first four terms are 20, 18, 16, 14. We see the sequence decreases by 2 each time, so the common difference $d = -2$. 4. The nth term formula for an arithmetic sequence is $a_n = a_1 + (n-1)d$. Here, $a_1 = 20$, $d = -2$, so: $$a_n = 20 + (n-1)(-2) = 20 - 2n + 2 = 22 - 2n$$ 5. Therefore, the missing nth term for Sequence B is $22 - 2n$. 6. For Sequence C, the nth term is given as $26 - 6n$. To find the first four terms, substitute $n=1,2,3,4$: - $a_1 = 26 - 6(1) = 20$ - $a_2 = 26 - 6(2) = 14$ - $a_3 = 26 - 6(3) = 8$ - $a_4 = 26 - 6(4) = 2$ 7. So the missing terms for Sequence C are 14, 8, and 2 for the 2nd, 3rd, and 4th terms respectively. Final answers: - Sequence B nth term: $22 - 2n$ - Sequence C terms: 14, 8, 2 This completes the missing information in the table.