Subjects algebra

Sequence Position

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1. **State the problem:** We are given the nth term of a sequence as $T(n) = 3n + 35$. 2. **Given:** A term in the sequence has a value of 347. We need to find the position $n$ of this term. 3. **Set up the equation:** Since $T(n) = 347$, substitute into the formula: $$3n + 35 = 347$$ 4. **Solve for $n$:** Subtract 35 from both sides: $$3n = 347 - 35$$ $$3n = 312$$ Divide both sides by 3: $$n = \frac{312}{3} = 104$$ 5. **Interpretation:** The term with value 347 is the 104th term in the sequence. **Final answer:** $n = 104$