1. The problem asks to find the 7th term of the sequence given by the formula $$a_n = \frac{n-1}{n^2 - 3}$$. 2. To find the 7th term, substitute $n=7$ into the formula: $$a_7 = \frac{7-1}{7^2 - 3}$$ 3. Simplify the numerator and denominator: $$a_7 = \frac{6}{49 - 3}$$ 4. Calculate the denominator: $$a_7 = \frac{6}{46}$$ 5. Simplify the fraction by dividing numerator and denominator by their greatest common divisor, which is 2: $$a_7 = \frac{\cancel{6}^3}{\cancel{46}^{23}}$$ 6. The simplest form of the 7th term is: $$a_7 = \frac{3}{23}$$