1. The problem asks for the first four terms of the sequence defined by the formula for the $n^{th}$ term: $$a_n = 8(3 - n)$$ 2. To find the first four terms, substitute $n = 1, 2, 3, 4$ into the formula. 3. Calculate each term: - For $n=1$: $$a_1 = 8(3 - 1) = 8 \times 2 = 16$$ - For $n=2$: $$a_2 = 8(3 - 2) = 8 \times 1 = 8$$ - For $n=3$: $$a_3 = 8(3 - 3) = 8 \times 0 = 0$$ - For $n=4$: $$a_4 = 8(3 - 4) = 8 \times (-1) = -8$$ 4. Therefore, the first four terms of the sequence are: $$16, 8, 0, -8$$