1. Stating the problem: We analyze the set $E = \{-\sqrt{3}; \frac{22}{7}; \sqrt{\frac{12}{27}}; \frac{\pi}{3}; \sqrt{0.90}; 0.12131415\}$ and points $A(3,2), M(3,2), N(-3,0)$, with segment $MN$ parallel to line $OJ$ where $OI$ and $OJ$ are perpendicular, each 1 cm.
2. Simplify elements of set $E$:
- $-\sqrt{3}$ remains $-\sqrt{3}$.
- $\frac{22}{7}$ is an approximation of $\pi$.
- $\sqrt{\frac{12}{27}}$ simplifies: $\frac{12}{27} = \frac{4}{9}$, so $\sqrt{\frac{12}{27}} = \sqrt{\frac{4}{9}} = \frac{2}{3}$.
- $\frac{\pi}{3}$ is approximately 1.047.
- $\sqrt{0.90} \approx 0.9487$.
- $0.12131415$ is a decimal number.
3. Find intersections of $E$ with known sets:
- $E \cap \mathbb{I}$ (irrational numbers): includes $-\sqrt{3}$ and $\pi/3$.
- $E \cap \mathbb{Z}$ (integers): none, no integers in $E$.
- $E \cap \mathbb{Q}$ (rationals): $\frac{22}{7}$ and $\frac{2}{3} = \sqrt{12/27}$ are rational.
4. Analyze points $A(3,2)$, $M(3,2)$, $N(-3,0)$ and segment $MN$ parallel to line $OJ$:
- Vector $\overrightarrow{MN} = (3 - (-3), 2 - 0) = (6,2)$.
- Since $OI$ and $OJ$ are perpendicular unit segments along axes, assume $OJ$ along x-axis: direction vector is $(1,0)$.
- $\overrightarrow{MN} = (6,2)$ is not parallel to $OJ$ as $(6,2)$ is not scalar multiple of $(1,0)$.
- If $OJ$ along y-axis $(0,1)$, again no parallelism since $(6,2)$ not scalar multiple of $(0,1)$.
5. Possibly $OJ$ direction vector differs; with data given, segment $MN$ is not parallel to unit $OJ$ along axes.
Final results:
- Simplified $E = \{-\sqrt{3}, \frac{22}{7}, \frac{2}{3}, \frac{\pi}{3}, \sqrt{0.90}, 0.12131415\}$.
- Irrationals in $E$: $\{-\sqrt{3}, \frac{\pi}{3}\}$.
- Rationals in $E$: $\{\frac{22}{7}, \frac{2}{3}, 0.12131415\}$ (assuming decimal is rational).
- No integers in $E$.
- $\overrightarrow{MN} = (6,2)$ is not parallel to $OJ$ if $OJ$ along standard axes.
Set Points Analysis
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.