1. The problem asks us to sketch the shifted exponential curves given by the functions $y=3^x+2$ and $y=3^{-x}+2$. 2. The general form of an exponential function is $y=a^x$, where $a>0$ and $a \neq 1$. Here, the functions are shifted vertically by 2 units, so the new functions are $y=3^x+2$ and $y=3^{-x}+2$. 3. For $y=3^x+2$, the base is 3, so the function grows exponentially as $x$ increases. The vertical shift of +2 moves the entire graph up by 2 units. The horizontal asymptote is $y=2$. 4. For $y=3^{-x}+2$, the base is $3^{-1} = \frac{1}{3}$, so the function decays exponentially as $x$ increases. The vertical shift of +2 also moves this graph up by 2 units. The horizontal asymptote is also $y=2$. 5. Both functions have the same horizontal asymptote $y=2$, but one grows and the other decays. 6. To summarize: - $y=3^x+2$ grows exponentially with asymptote $y=2$. - $y=3^{-x}+2$ decays exponentially with asymptote $y=2$. These are the shifted exponential curves as requested.