1. The problem asks to identify the function $g(x)$ given the graph of $f(x) = \sqrt{x}$ and the graph of $g(x)$ which looks like a shifted version of $f(x)$. 2. The function $f(x) = \sqrt{x}$ starts at the origin $(0,0)$ and increases as $x$ increases. 3. Observing the graph, $g(x)$ appears to be the same shape as $f(x)$ but shifted to the right by 1 unit. This means the input to the square root function is shifted. 4. The general form for a horizontal shift of a function $f(x)$ is $f(x - h)$, where $h$ is the shift amount to the right. 5. Since $g(x)$ starts at $(1,0)$ instead of $(0,0)$, the shift is $h = 1$. 6. Therefore, $g(x) = \sqrt{x - 1}$. 7. This means for any $x \geq 1$, $g(x)$ outputs the square root of $x - 1$, matching the blue graph. Final answer: $$g(x) = \sqrt{x - 1}$$