1. **State the problem:** We have counts of consumers shopping at different stores and combinations of stores. We want to find: - The percent of consumers who shopped at more than one store. - The percent of consumers who shopped exclusively at Nordstrom. 2. **Identify the data:** - 1248: Macy's only - 1322: Scheels only - 1498: Nordstrom only - 2399: Macy's and Scheels - 2236: Scheels and Nordstrom - 2110: Macy's and Nordstrom - 288: All three stores - 158: Shopped at none 3. **Calculate total consumers:** $$\text{Total} = 1248 + 1322 + 1498 + 2399 + 2236 + 2110 + 288 + 158 = 11059$$ 4. **Calculate consumers who shopped at more than one store:** These are those who shopped at exactly two stores plus those who shopped at all three: $$\text{More than one store} = 2399 + 2236 + 2110 + 288 = 7033$$ 5. **Calculate percent who shopped at more than one store:** $$\text{Percent} = \frac{7033}{11059} \times 100$$ Intermediate step showing cancellation: $$\frac{\cancel{7033}}{\cancel{11059}} \times 100$$ Calculate the value: $$\approx 63.6\%$$ 6. **Calculate percent who shopped exclusively at Nordstrom:** $$\text{Nordstrom only} = 1498$$ $$\text{Percent} = \frac{1498}{11059} \times 100$$ Intermediate step showing cancellation: $$\frac{\cancel{1498}}{\cancel{11059}} \times 100$$ Calculate the value: $$\approx 13.5\%$$ **Final answers:** 1. Approximately **63.6 percent** of consumers shopped at more than one store. 2. Approximately **13.5 percent** of consumers shopped exclusively at Nordstrom.