Subjects algebra

Simple Interest 9F69Ae

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1. The problem is to calculate the simple interest $I$ using the formula: $$I = prt$$ where $p$ is the principal amount, $r$ is the rate of interest per year (in decimal), and $t$ is the time in years. 2. For the first example, the values are $p=690$, $t=12$, and $r=0.05$. 3. Substitute these values into the formula: $$I = 690 \times 0.05 \times 12$$ 4. Calculate the product: $$I = 690 \times 0.6 = 414$$ 5. The interest earned is $414$. 6. For the second example, $p=1200$, $t=10$, and $r=0.015$. 7. Substitute and calculate: $$I = 1200 \times 0.015 \times 10 = 1200 \times 0.15 = 180$$ 8. The interest earned is $180$. 9. For the third example, $p=1500$, $r=0.03$, but $t$ is missing, so we cannot calculate $I$ without $t$. 10. The remaining lines do not provide enough information to calculate interest. Final answer for the first problem: $I = 414$. q_count is 3 because there are three distinct problems with given data.