1. **Stating the problem:** We have a table with two columns: one labeled $m$ and the other labeled $\frac{2m}{2}$. We need to fill in the missing values in the table. 2. **Understanding the formula:** The second column is $\frac{2m}{2}$. Simplifying this expression: $$\frac{2m}{2} = \cancel{\frac{2}{2}} m = m$$ This means the second column is actually equal to $m$. 3. **Using the formula to fill the table:** Since $\frac{2m}{2} = m$, the values in the second column must be equal to the corresponding $m$ values. 4. **Filling in the blanks:** - For row (a), $m=6$, so $\frac{2m}{2} = 6$. - For row (b), the denominator is 4, so $\frac{2m}{2} = \frac{m}{1} = m$. Since the denominator is 4, the numerator must be $4$ times $m$. But since $\frac{2m}{2} = m$, the fraction $\frac{?}{4}$ equals $m$, so $m = \frac{?}{4} \Rightarrow ? = 4m$. We need to find $m$ first. - For row (c), $m=12$, so $\frac{2m}{2} = 12$. - For row (d), $m=10$, so $\frac{2m}{2} = 10$. - For row (e), the denominator is 8, so $\frac{?}{8} = m \Rightarrow ? = 8m$. We need to find $m$ first. 5. **Using the known values to find missing $m$ values:** From the table, the only missing $m$ values are in rows (b) and (e). 6. **Assuming the fractions in the second column correspond to $\frac{2m}{2}$, which equals $m$, the fractions $\frac{?}{4}$ and $\frac{?}{8}$ must equal $m$ in rows (b) and (e) respectively. So: - For (b): $m = \frac{?}{4}$ - For (e): $m = \frac{?}{8}$ Since $m$ is missing in these rows, but the fractions are given as $\frac{?}{4}$ and $\frac{?}{8}$, we can only express $m$ in terms of the numerator. 7. **Final filled table:** - (a) $m=6$, $\frac{2m}{2} = 6$ - (b) $m=\frac{?}{4}$, $\frac{2m}{2} = m$ - (c) $m=12$, $\frac{2m}{2} = 12$ - (d) $m=10$, $\frac{2m}{2} = 10$ - (e) $m=\frac{?}{8}$, $\frac{2m}{2} = m$ Since the problem does not provide more data, the key takeaway is that $\frac{2m}{2} = m$, so the second column equals the first column. **Final answer:** The second column values are equal to the $m$ values in the first column.