1. **State the problem:** Simplify the expression $(+4ab-5ab)\times(+3ab+5a^2-3-5ab)$.\n\n2. **Simplify inside the parentheses:**\n\nFirst, simplify $+4ab-5ab$:\n$$+4ab-5ab=\cancel{4ab}-\cancel{5ab}=-1ab=-ab$$\n\n3. **Rewrite the expression:**\n$$(-ab)\times(+3ab+5a^2-3-5ab)$$\n\n4. **Simplify the second parentheses:**\nGroup like terms $+3ab$ and $-5ab$:\n$$+3ab-5ab=\cancel{3ab}-\cancel{5ab}=-2ab$$\nSo the second parentheses become:\n$$-2ab+5a^2-3$$\n\n5. **Rewrite the expression:**\n$$(-ab)\times(-2ab+5a^2-3)$$\n\n6. **Distribute $-ab$ over each term:**\n$$(-ab)(-2ab) + (-ab)(5a^2) + (-ab)(-3)$$\n\n7. **Calculate each product:**\n- $(-ab)(-2ab) = 2a^2b^2$\n- $(-ab)(5a^2) = -5a^3b$\n- $(-ab)(-3) = 3ab$\n\n8. **Combine all terms:**\n$$2a^2b^2 - 5a^3b + 3ab$$\n\n**Final answer:**\n$$\boxed{2a^2b^2 - 5a^3b + 3ab}$$