1. **State the problem:** Simplify the expression $$\frac{y^2 y^0}{y^{-2}}$$. 2. **Recall exponent rules:** - Any number to the zero power is 1, so $$y^0 = 1$$. - When multiplying powers with the same base, add exponents: $$a^m \cdot a^n = a^{m+n}$$. - When dividing powers with the same base, subtract exponents: $$\frac{a^m}{a^n} = a^{m-n}$$. 3. **Apply these rules step-by-step:** $$\frac{y^2 \cdot y^0}{y^{-2}} = \frac{y^2 \cdot 1}{y^{-2}} = \frac{y^2}{y^{-2}}$$ 4. **Use division rule for exponents:** $$\frac{y^2}{y^{-2}} = y^{2 - (-2)} = y^{2 + 2} = y^4$$ 5. **Final answer:** $$y^4$$