1. The problem involves simplifying the expression $2^{\log_2(4x^2)}$. 2. Recall the logarithm and exponent rules: $a^{\log_a(b)} = b$ for any positive $a \neq 1$. 3. Here, the base of the exponent and the logarithm is 2, so we can apply the rule directly. 4. Therefore, $2^{\log_2(4x^2)} = 4x^2$. 5. To simplify further, note that $4 = 2^2$, so $4x^2 = 2^2 x^2 = (2x)^2$. 6. The final simplified form is $\boxed{(2x)^2}$ or simply $4x^2$.