1. **State the problem:** Simplify the expression $3^{-3} \times 27^2 \times (9^4)^{-5}$. 2. **Rewrite all terms with the same base:** Note that $27 = 3^3$ and $9 = 3^2$. So rewrite the expression as $$3^{-3} \times (3^3)^2 \times \left((3^2)^4\right)^{-5}$$ 3. **Apply power of a power rule:** $(a^m)^n = a^{mn}$, so $$3^{-3} \times 3^{3 \times 2} \times 3^{2 \times 4 \times (-5)}$$ which simplifies to $$3^{-3} \times 3^{6} \times 3^{-40}$$ 4. **Combine powers with the same base:** $a^m \times a^n = a^{m+n}$, so $$3^{-3 + 6 - 40} = 3^{-37}$$ 5. **Final answer:** $$\boxed{3^{-37}}$$