1. **State the problem:** Simplify the expression $$\frac{-6 - \frac{6}{3^2} - (-3)}{} - \frac{-7 - \frac{5}{7^1} - 6}{}$$ using the order of operations. 2. **Rewrite the expression clearly:** $$-6 - \frac{6}{3^2} - (-3) - \left(-7 - \frac{5}{7} - 6\right)$$ 3. **Calculate powers:** $$3^2 = 9$$ $$7^1 = 7$$ 4. **Substitute powers back:** $$-6 - \frac{6}{9} - (-3) - \left(-7 - \frac{5}{7} - 6\right)$$ 5. **Simplify fractions:** $$\frac{6}{9} = \frac{2}{3}$$ 6. **Rewrite expression:** $$-6 - \frac{2}{3} - (-3) - \left(-7 - \frac{5}{7} - 6\right)$$ 7. **Simplify inside the parentheses:** Calculate $$-7 - \frac{5}{7} - 6$$ Convert to common denominator 7: $$-7 = -\frac{49}{7}, \quad -6 = -\frac{42}{7}$$ Sum: $$-\frac{49}{7} - \frac{5}{7} - \frac{42}{7} = -\frac{49 + 5 + 42}{7} = -\frac{96}{7}$$ 8. **Rewrite expression:** $$-6 - \frac{2}{3} - (-3) - \left(-\frac{96}{7}\right)$$ 9. **Simplify double negatives:** $$-6 - \frac{2}{3} + 3 + \frac{96}{7}$$ 10. **Combine integer terms:** $$-6 + 3 = -3$$ Expression becomes: $$-3 - \frac{2}{3} + \frac{96}{7}$$ 11. **Find common denominator for fractions and integer:** Common denominator is 21. Rewrite each term: $$-3 = -\frac{63}{21}, \quad -\frac{2}{3} = -\frac{14}{21}, \quad \frac{96}{7} = \frac{288}{21}$$ 12. **Sum all terms:** $$-\frac{63}{21} - \frac{14}{21} + \frac{288}{21} = \frac{-63 - 14 + 288}{21} = \frac{211}{21}$$ 13. **Final answer:** $$\boxed{\frac{211}{21}}$$