1. **State the problem:** Simplify the expression $2(2+6b) - 3(4b-2)$. 2. **Apply the distributive property:** Multiply each term inside the parentheses by the factor outside. $$2(2+6b) = 2 \times 2 + 2 \times 6b = 4 + 12b$$ $$-3(4b-2) = -3 \times 4b + (-3) \times (-2) = -12b + 6$$ 3. **Rewrite the expression with distributed terms:** $$4 + 12b - 12b + 6$$ 4. **Combine like terms:** The terms $12b$ and $-12b$ cancel each other out, so we have: $$4 + \cancel{12b} - \cancel{12b} + 6 = 4 + 6$$ 5. **Add the constants:** $$4 + 6 = 10$$ **Final answer:** $$10$$