1. The problem appears to involve simplifying or solving an expression involving $y + 3$, $1$, and $y - 2$. However, the exact operation is unclear from the input. 2. Assuming the problem is to simplify the expression $\frac{y+3}{1} \times (y-2)$, we use the property that dividing by 1 does not change the value. 3. So, the expression simplifies to: $$\frac{y+3}{\cancel{1}} \times (y-2) = (y+3)(y-2)$$ 4. Next, we expand the product using the distributive property: $$ (y+3)(y-2) = y \times y + y \times (-2) + 3 \times y + 3 \times (-2) $$ $$ = y^2 - 2y + 3y - 6 $$ 5. Combine like terms: $$ y^2 + ( -2y + 3y ) - 6 = y^2 + y - 6 $$ 6. Therefore, the simplified expression is: $$ y^2 + y - 6 $$ This is the final answer.