1. **State the problem:** Simplify the expression $$\frac{-28a^{16}b^{8}c^{5}}{7a^{11}b^{5}c^{5}}$$. 2. **Recall the rules:** - When dividing powers with the same base, subtract the exponents: $$\frac{x^m}{x^n} = x^{m-n}$$. - Any term divided by itself cancels out. 3. **Simplify the coefficients:** $$\frac{-28}{7} = -4$$ 4. **Simplify the variables:** $$\frac{a^{16}}{a^{11}} = a^{16-11} = a^{5}$$ $$\frac{b^{8}}{b^{5}} = b^{8-5} = b^{3}$$ $$\frac{c^{5}}{c^{5}} = c^{5-5} = c^{0} = 1$$ 5. **Combine all simplified parts:** $$-4 \times a^{5} \times b^{3} \times 1 = -4a^{5}b^{3}$$ **Final answer:** $$\boxed{-4a^{5}b^{3}}$$