1. The problem asks to simplify the fraction $\frac{120}{500}$.
2. To simplify a fraction, we divide the numerator and denominator by their greatest common divisor (GCD).
3. Find the GCD of 120 and 500.
- Prime factors of 120: $2^3 \times 3 \times 5$
- Prime factors of 500: $2^2 \times 5^3$
- Common factors: $2^2 \times 5 = 20$
4. Divide numerator and denominator by 20:
$$\frac{120}{500} = \frac{\cancel{20} \times 6}{\cancel{20} \times 25} = \frac{6}{25}$$
5. The simplified fraction is $\frac{6}{25}$.
Simplify Fraction Ebf31B
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