1. The problem is to simplify the radical expression $\sqrt{160}$. 2. Recall the rule for simplifying radicals: $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$. 3. Find the largest perfect square factor of 160. Since $16$ is a perfect square and $16 \times 10 = 160$, we write: $$\sqrt{160} = \sqrt{16 \times 10}$$ 4. Apply the product rule for square roots: $$\sqrt{160} = \sqrt{16} \times \sqrt{10}$$ 5. Simplify $\sqrt{16}$ since $16$ is a perfect square: $$\sqrt{16} = 4$$ 6. Therefore: $$\sqrt{160} = 4 \times \sqrt{10} = 4\sqrt{10}$$ 7. The simplest radical form of $\sqrt{160}$ is $4\sqrt{10}$.