1. **State the problem:** Simplify the expression $$x^2\sqrt{x^2}$$ assuming $$x > 0$$. 2. **Recall the properties:** The square root of $$x^2$$ is $$|x|$$, but since $$x > 0$$, $$\sqrt{x^2} = x$$. 3. **Rewrite the expression:** $$x^2\sqrt{x^2} = x^2 \cdot x$$ 4. **Multiply the powers of $$x$$:** $$x^2 \cdot x = x^{2+1} = x^3$$ 5. **Final answer:** $$x^3$$ Thus, the simplest radical form of $$x^2\sqrt{x^2}$$ for $$x > 0$$ is $$x^3$$.