1. **State the problem:** Simplify the expression $$\frac{\sqrt{3} \left(3 + \sqrt{\frac{2}{3}}\right) \sqrt{3}}{\sqrt{3}}$$.
2. **Rewrite the expression:** The numerator is $$\sqrt{3} \times \left(3 + \sqrt{\frac{2}{3}}\right) \times \sqrt{3}$$ and the denominator is $$\sqrt{3}$$.
3. **Multiply the terms in the numerator:** Since $$\sqrt{3} \times \sqrt{3} = 3$$, the numerator becomes $$3 \times \left(3 + \sqrt{\frac{2}{3}}\right)$$.
4. **Write the expression now:** $$\frac{3 \left(3 + \sqrt{\frac{2}{3}}\right)}{\sqrt{3}}$$.
5. **Distribute the 3 in the numerator:** $$\frac{9 + 3 \sqrt{\frac{2}{3}}}{\sqrt{3}}$$.
6. **Simplify the term inside the square root:** $$\sqrt{\frac{2}{3}} = \frac{\sqrt{2}}{\sqrt{3}}$$.
7. **Substitute back:** $$\frac{9 + 3 \times \frac{\sqrt{2}}{\sqrt{3}}}{\sqrt{3}} = \frac{9 + \frac{3 \sqrt{2}}{\sqrt{3}}}{\sqrt{3}}$$.
8. **Combine the terms over a common denominator:** Write 9 as $$\frac{9 \sqrt{3}}{\sqrt{3}}$$ to have a common denominator $$\sqrt{3}$$:
$$\frac{\frac{9 \sqrt{3}}{\sqrt{3}} + \frac{3 \sqrt{2}}{\sqrt{3}}}{\sqrt{3}} = \frac{\frac{9 \sqrt{3} + 3 \sqrt{2}}{\sqrt{3}}}{\sqrt{3}}$$.
9. **Simplify the complex fraction:** $$\frac{\frac{9 \sqrt{3} + 3 \sqrt{2}}{\sqrt{3}}}{\sqrt{3}} = \frac{9 \sqrt{3} + 3 \sqrt{2}}{\sqrt{3} \times \sqrt{3}} = \frac{9 \sqrt{3} + 3 \sqrt{2}}{3}$$.
10. **Factor out 3 in the numerator:** $$\frac{3 (3 \sqrt{3} + \sqrt{2})}{3}$$.
11. **Cancel the 3 in numerator and denominator:** $$\frac{\cancel{3} (3 \sqrt{3} + \sqrt{2})}{\cancel{3}} = 3 \sqrt{3} + \sqrt{2}$$.
**Final answer:** $$3 \sqrt{3} + \sqrt{2}$$
Simplify Radical Expression 331324
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