1. The problem involves simplifying the expression $\frac{\sqrt{33} \pi}{\sqrt{3}}$. 2. Recall the property of radicals: $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$. 3. Apply this property: $$\frac{\sqrt{33} \pi}{\sqrt{3}} = \pi \cdot \frac{\sqrt{33}}{\sqrt{3}} = \pi \cdot \sqrt{\frac{33}{3}}$$ 4. Simplify inside the square root: $$\sqrt{\frac{33}{3}} = \sqrt{11}$$ 5. So the expression simplifies to: $$\pi \sqrt{11}$$ Final answer: $\pi \sqrt{11}$