1. **State the problem:** Simplify the expression $3\sqrt{x}7 + 1 + 2\sqrt{x}7$. 2. **Rewrite the expression:** Notice that $\sqrt{x}7$ is ambiguous, but assuming it means $7\sqrt{x}$, the expression becomes: $$3 \times 7 \sqrt{x} + 1 + 2 \times 7 \sqrt{x} = 21\sqrt{x} + 1 + 14\sqrt{x}$$ 3. **Combine like terms:** The terms $21\sqrt{x}$ and $14\sqrt{x}$ are like terms because they both contain $\sqrt{x}$. $$21\sqrt{x} + 14\sqrt{x} = (21 + 14)\sqrt{x} = 35\sqrt{x}$$ 4. **Write the simplified expression:** $$35\sqrt{x} + 1$$ **Final answer:** $35\sqrt{x} + 1$