1. Problem: Find the product in simplest radical form for $\sqrt{18} \cdot \sqrt{12}$. 2. Use the property of radicals: $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$. 3. Calculate the product inside the radical: $\sqrt{18 \cdot 12} = \sqrt{216}$. 4. Simplify $\sqrt{216}$ by factoring 216 into prime factors: $216 = 36 \times 6$. 5. Use the property $\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$ again: $\sqrt{216} = \sqrt{36} \cdot \sqrt{6}$. 6. Since $\sqrt{36} = 6$, the expression simplifies to $6 \sqrt{6}$. Final answer: $6 \sqrt{6}$.