Subjects algebra

Simplify Radicals 61084F

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1. **State the problem:** Simplify the expression $3\sqrt{48} - \sqrt{12}$. 2. **Recall the rule:** $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$ and simplify square roots by factoring out perfect squares. 3. Simplify $\sqrt{48}$: $$\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3}$$ 4. Simplify $\sqrt{12}$: $$\sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3}$$ 5. Substitute back: $$3\sqrt{48} - \sqrt{12} = 3 \times 4\sqrt{3} - 2\sqrt{3} = 12\sqrt{3} - 2\sqrt{3}$$ 6. Combine like terms: $$12\sqrt{3} - 2\sqrt{3} = (12 - 2)\sqrt{3} = 10\sqrt{3}$$ **Final answer:** $10\sqrt{3}$