1. The problem is to simplify the expression $\sqrt{8} - \sqrt{60}$. 2. Recall that the square root of a product can be written as the product of square roots: $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$. 3. Factor the numbers inside the square roots to extract perfect squares: $$\sqrt{8} = \sqrt{4 \times 2} = \sqrt{4} \times \sqrt{2} = 2\sqrt{2}$$ $$\sqrt{60} = \sqrt{4 \times 15} = \sqrt{4} \times \sqrt{15} = 2\sqrt{15}$$ 4. Substitute back into the expression: $$\sqrt{8} - \sqrt{60} = 2\sqrt{2} - 2\sqrt{15}$$ 5. Factor out the common factor 2: $$2\sqrt{2} - 2\sqrt{15} = 2(\sqrt{2} - \sqrt{15})$$ 6. This is the simplified form since $\sqrt{2}$ and $\sqrt{15}$ are unlike terms and cannot be combined further. **Final answer:** $$2(\sqrt{2} - \sqrt{15})$$