Subjects algebra

Simplify Rational Expression 41B2Cb

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1. **State the problem:** Simplify the expression $$\frac{3x+4}{x} - \frac{5}{6x} + \frac{9}{2x}$$. 2. **Identify the common denominator:** The denominators are $x$, $6x$, and $2x$. The least common denominator (LCD) is $6x$. 3. **Rewrite each term with the LCD:** $$\frac{3x+4}{x} = \frac{(3x+4) \times 6}{6x} = \frac{18x + 24}{6x}$$ $$\frac{5}{6x} = \frac{5}{6x}$$ $$\frac{9}{2x} = \frac{9 \times 3}{2x \times 3} = \frac{27}{6x}$$ 4. **Combine the terms over the common denominator:** $$\frac{18x + 24}{6x} - \frac{5}{6x} + \frac{27}{6x} = \frac{18x + 24 - 5 + 27}{6x}$$ 5. **Simplify the numerator:** $$18x + 24 - 5 + 27 = 18x + (24 - 5 + 27) = 18x + 46$$ 6. **Final simplified expression:** $$\frac{18x + 46}{6x}$$ 7. **Factor numerator if possible:** $$18x + 46 = 2(9x + 23)$$ 8. **Simplify the fraction by canceling common factors:** $$\frac{2(9x + 23)}{6x} = \frac{\cancel{2}(9x + 23)}{\cancel{6}x} = \frac{9x + 23}{3x}$$ **Answer:** $$\boxed{\frac{9x + 23}{3x}}$$