1. **State the problem:** Simplify the expression $$\frac{2 \left( \frac{4}{2-x} \right) - 4}{x}$$. 2. **Rewrite the numerator:** Multiply inside the parentheses: $$2 \times \frac{4}{2-x} = \frac{8}{2-x}$$ So the numerator becomes: $$\frac{8}{2-x} - 4$$ 3. **Find a common denominator for the numerator:** Rewrite 4 as $\frac{4(2-x)}{2-x}$: $$\frac{8}{2-x} - \frac{4(2-x)}{2-x} = \frac{8 - 4(2-x)}{2-x}$$ 4. **Simplify the numerator inside the fraction:** $$8 - 4(2-x) = 8 - 8 + 4x = 4x$$ 5. **So the numerator is:** $$\frac{4x}{2-x}$$ 6. **Rewrite the entire expression:** $$\frac{\frac{4x}{2-x}}{x}$$ 7. **Divide by $x$ by multiplying by its reciprocal:** $$\frac{4x}{2-x} \times \frac{1}{x} = \frac{4x}{2-x} \times \frac{1}{x}$$ 8. **Cancel common factors:** $$\frac{\cancel{4x}}{2-x} \times \frac{1}{\cancel{x}} = \frac{4}{2-x}$$ **Final answer:** $$\boxed{\frac{4}{2-x}}$$