1. **State the problem:** Simplify the expression and solve the equation if possible. Given expressions: $$2x - 3x - 1 + \frac{4}{5}$$ $$2ux + 3x - 2$$ $$2ux + 3x - 2 = 0$$ $$+ 9x - 3$$ 2. **Simplify the first expression:** $$2x - 3x - 1 + \frac{4}{5} = (2x - 3x) - 1 + \frac{4}{5} = -x - 1 + \frac{4}{5}$$ 3. **Combine constants:** $$-1 + \frac{4}{5} = -\frac{5}{5} + \frac{4}{5} = -\frac{1}{5}$$ So the first expression simplifies to: $$-x - \frac{1}{5}$$ 4. **Analyze the second expression:** $$2ux + 3x - 2$$ This expression depends on the variable $u$ and $x$. 5. **Solve the equation:** $$2ux + 3x - 2 = 0$$ Factor out $x$: $$x(2u + 3) - 2 = 0$$ Add 2 to both sides: $$x(2u + 3) = 2$$ Divide both sides by $2u + 3$ (assuming $2u + 3 \neq 0$): $$x = \frac{2}{\cancel{2u + 3}} \cancel{\frac{1}{2u + 3}} = \frac{2}{2u + 3}$$ 6. **The last expression $+ 9x - 3$ is incomplete and cannot be simplified further without context.** **Final answers:** - Simplified expression: $$-x - \frac{1}{5}$$ - Solution for $x$ in the equation $2ux + 3x - 2 = 0$ is $$x = \frac{2}{2u + 3}$$