1. The problem is to simplify the expression $\sqrt{27}$. 2. Recall that $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$, which allows us to break down the radicand into factors. 3. Factor 27 into $9 \times 3$ because 9 is a perfect square. 4. Apply the property: $$\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \times \sqrt{3}$$ 5. Since $\sqrt{9} = 3$, substitute this back: $$\sqrt{27} = 3 \times \sqrt{3}$$ 6. Therefore, the simplified form of $\sqrt{27}$ is $3\sqrt{3}$.