1. **State the problem:** Simplify the expression $\sqrt{3} \cdot \sqrt{2}$. 2. **Recall the property of square roots:** The product of square roots can be combined as $\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}$. 3. **Apply the property:** $$\sqrt{3} \cdot \sqrt{2} = \sqrt{3 \cdot 2}$$ 4. **Multiply inside the square root:** $$\sqrt{6}$$ 5. **Final answer:** The simplified form of $\sqrt{3} \cdot \sqrt{2}$ is $\sqrt{6}$. This means multiplying the two square roots is equivalent to taking the square root of their product.