1. **State the problem:** Solve the simultaneous equations:
$$y - 2x = 10$$
$$2x + 5y = 26$$
2. **Rewrite the first equation to express $y$ in terms of $x$: **
$$y = 2x + 10$$
3. **Substitute $y = 2x + 10$ into the second equation:**
$$2x + 5(2x + 10) = 26$$
4. **Expand and simplify:**
$$2x + 10x + 50 = 26$$
$$12x + 50 = 26$$
5. **Isolate $x$ by subtracting 50 from both sides:**
$$12x + \cancel{50} - \cancel{50} = 26 - 50$$
$$12x = -24$$
6. **Divide both sides by 12 to solve for $x$:**
$$\frac{12x}{\cancel{12}} = \frac{-24}{\cancel{12}}$$
$$x = -2$$
7. **Substitute $x = -2$ back into $y = 2x + 10$ to find $y$:**
$$y = 2(-2) + 10 = -4 + 10 = 6$$
8. **Final solution:**
$$\boxed{(x, y) = (-2, 6)}$$
This is the point where the red and green lines intersect on the graph, confirming the solution to the simultaneous equations.
Simultaneous Equations 0Ae0Dc
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