1. **State the problem:** Solve the simultaneous equations using substitution: $$7x - 2y = 27$$ $$y + 12 = 2x$$ 2. **Isolate one variable:** From the second equation, isolate $y$: $$y = 2x - 12$$ 3. **Substitute into the first equation:** Replace $y$ in the first equation with $2x - 12$: $$7x - 2(2x - 12) = 27$$ 4. **Simplify the equation:** $$7x - \cancel{2}(2x - 12) = 27$$ $$7x - (4x - 24) = 27$$ $$7x - 4x + 24 = 27$$ 5. **Combine like terms:** $$3x + 24 = 27$$ 6. **Isolate $x$:** $$3x = 27 - 24$$ $$3x = 3$$ 7. **Solve for $x$:** $$x = \frac{3}{3}$$ $$x = 1$$ 8. **Find $y$ using $x=1$:** Substitute $x=1$ into $y = 2x - 12$: $$y = 2(1) - 12$$ $$y = 2 - 12$$ $$y = -10$$ **Final answer:** $$x = 1, \quad y = -10$$