1. **State the problem:** We have two functions, A and B, with different rates of change (slopes). We want to find the equation of a new linear function whose slope is an integer between the slopes of A and B. 2. **Find the slope of Function A:** Using points (-4, -9) and (0, 4), slope $m_A = \frac{4 - (-9)}{0 - (-4)} = \frac{13}{4} = 3.25$. 3. **Find the slope of Function B:** From the graph description, Function B passes through (0,1) and is steep. Using points (-10, -2) and (0,1) from the table, slope $m_B = \frac{1 - (-2)}{0 - (-10)} = \frac{3}{10} = 0.3$. However, the y-values given for Function B are $10,8,6,4,2$ corresponding to $x = -10, -8, -6, -4, -2$ and so on, which suggests the slope is negative. Using points (-10,10) and (-8,8), slope $m_B = \frac{8 - 10}{-8 - (-10)} = \frac{-2}{2} = -1$. 4. **Compare slopes:** $m_A = 3.25$, $m_B = -1$. We want an integer slope $m$ such that $-1 < m < 3.25$. Possible integer slopes are $0,1,2,3$. 5. **Choose a slope between the two:** Let's pick $m = 2$. 6. **Find the y-intercept $b$ for the new function:** Use point (0,4) from Function A (since it lies on y-axis) for simplicity. Equation: $y = mx + b$. Plug in $x=0$, $y=4$: $$4 = 2 \times 0 + b \Rightarrow b = 4$$ 7. **Final equation:** $$y = 2x + 4$$ This function has a slope between the slopes of Function A and Function B and uses integers for slope and intercept.