1. **Problem Statement:** Determine the slope of the linear relations shown in tables b and c. 2. **Formula for slope:** The slope $m$ of a linear relation given two points $(x_1, y_1)$ and $(x_2, y_2)$ is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ This formula calculates the rate of change of $y$ with respect to $x$. 3. **Calculate slope for table b:** Points: $(0,8)$ and $(-2,12)$ $$m = \frac{12 - 8}{-2 - 0} = \frac{4}{-2}$$ Cancel common factor: $$m = \frac{\cancel{4}}{\cancel{-2}} = -2$$ So, slope $m = -2$. 4. **Calculate slope for table c:** Points: $(-1,9)$ and $(0,6)$ $$m = \frac{6 - 9}{0 - (-1)} = \frac{-3}{1} = -3$$ No cancellation needed here. 5. **Final answers:** - For table b, slope $m = -2$ - For table c, slope $m = -3$